How do you figure out the molecular formula of oxalic acid?

So here’s the question:
Oxalic acid occurs naturally in rhubarb leaves. It contains 26.7% carbon, 71.1% oxygen and 2.22% hydrogen by mass. 0.52 mol of the compound has a mass of 46.8 g. Find the molecular formula of oxalic acid.

So i firstly did the empirical formula and its CO2 H (the 2 is surposed to be little)
im just not quite sure what to do next
if you could help that would be great!

since .52 moles weigh 46.8 gm the molecular weight is 46.8/ .52

= 90 gm

adding the atomic masses of your empirical formula gives 45 amu so the the molecular formula is 2 * empirical formula or

C2O4H2 = 90 g / mol

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